Oka and uma: Difference between revisions

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#Before playing, calculate <code>Final Score - (raw score / 1000)</code> for each place. Use dummy numbers for raw score.
#Before playing, calculate <code>Final Score - (raw score / 1000)</code> for each place. Use dummy numbers for raw score.
#After finishing the game, find the raw score, round it to the nearest 1,000, then divide by 1,000.
#After finishing the game, find the raw score, round it to the nearest 1,000 (rounding 500 down), then divide by 1,000.
#Use the calculated values from #1 to quickly determine final scores.
#Use the calculated values from #1 to quickly determine final scores.


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This means, for these oka/uma settings, 1st place final score is equal to <code>(raw score/1000) + 10</code>, 2nd place final score is equal to <code>(raw score/1000) - 20</code>, and so on.
This means, for these oka/uma settings, 1st place final score is equal to <code>(raw score/1000) + 10</code>, 2nd place final score is equal to <code>(raw score/1000) - 20</code>, and so on. In other words: instead of having to calculate oka and uma every single time, when you are 1st with these settings, you can divide score by 1000, then add 10.


Using the above picture as another example:
Using the above picture as another example:
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When scores are tied, there are two main variations to how it is handled:
When scores are tied, there are two main variations to how it is handled:
* Ties are broken based on the initial [[Jikaze|wind seating]] (seats in the first hand). When scores are tied, East beats South beats West beats North.  
* Ties are broken based on the initial [[Jikaze|wind seating]] (seats in the first hand). When scores are tied, the initial East player beats South beats West beats North.  
* Tied players split oka/uma bonuses evenly. For example, with an uma of {{Uma|20|10|-10|-20}}, if two players tie for 3rd, they would pay (-10 + -20) / 2 = -15 each.
* Tied players split oka/uma bonuses evenly. For example, with an uma of {{Uma|20|10|-10|-20}}, if two players tie for 3rd, they would pay (-10 + -20) / 2 = -15 each.


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