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Oka and uma: Difference between revisions
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#Before playing, calculate <code>Final Score - (raw score / 1000)</code> for each place. Use dummy numbers for raw score. | #Before playing, calculate <code>Final Score - (raw score / 1000)</code> for each place. Use dummy numbers for raw score. | ||
#After finishing the game, find the raw score, round it to the nearest 1,000, then divide by 1,000. | #After finishing the game, find the raw score, round it to the nearest 1,000 (rounding 500 down), then divide by 1,000. | ||
#Use the calculated values from #1 to quickly determine final scores. | #Use the calculated values from #1 to quickly determine final scores. | ||
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This means, for these oka/uma settings, 1st place final score is equal to <code>(raw score/1000) + 10</code>, 2nd place final score is equal to <code>(raw score/1000) - 20</code>, and so on. | This means, for these oka/uma settings, 1st place final score is equal to <code>(raw score/1000) + 10</code>, 2nd place final score is equal to <code>(raw score/1000) - 20</code>, and so on. In other words: instead of having to calculate oka and uma every single time, when you are 1st with these settings, you can divide score by 1000, then add 10. | ||
Using the above picture as another example: | Using the above picture as another example: | ||
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When scores are tied, there are two main variations to how it is handled: | When scores are tied, there are two main variations to how it is handled: | ||
* Ties are broken based on the initial [[Jikaze|wind seating]] (seats in the first hand). When scores are tied, East beats South beats West beats North. | * Ties are broken based on the initial [[Jikaze|wind seating]] (seats in the first hand). When scores are tied, the initial East player beats South beats West beats North. | ||
* Tied players split oka/uma bonuses evenly. For example, with an uma of {{Uma|20|10|-10|-20}}, if two players tie for 3rd, they would pay (-10 + -20) / 2 = -15 each. | * Tied players split oka/uma bonuses evenly. For example, with an uma of {{Uma|20|10|-10|-20}}, if two players tie for 3rd, they would pay (-10 + -20) / 2 = -15 each. | ||